Re:Need Something Sorted? Sleep on It
by david_allison on Monday May 24, 2021 @10:40PM
(#27272075)
Let's do better.
You can find the largest element in a list in O(1) time with n^2 processors[0]*.
Division of the list by that number is O(1) with n processors
Therefore the operation is O(1)
[0]* on a CRCW PRAM https://www.cpp.edu/~gsyoung/CS535/CS535Notes/Part2PRAM.pdf#...
Edit:
Why divide by m, when you can divide by M*C. Where C will speed this portion up by a factor!