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Re:Show HN: Diffie-Hellman exchange for the layman by anon_tor_12345 on Thursday April 22, 2021 @10:30AM (#26903164)
>pq mod r == ((p mod r) * (q mod r)) mod r

that's just multiplication in Z_r...?

edit: alright i guess technically it uses homomorphism from Z to Z_r but you don't need to be able to write out the proof to intuit/believe it

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