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A comment on Euler's Fizzbuzz (2020). Parent comment
In general (ab) mod n == (a mod n)(b mod n) mod n
In the case of (3*c)^4, 3^4 mod 15 -> 108 mod 15 -> 3.
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In general (ab) mod n == (a mod n)(b mod n) mod n
In the case of (3*c)^4, 3^4 mod 15 -> 108 mod 15 -> 3.