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A comment on Euler's Fizzbuzz (2020). Parent comment

Re:Euler's Fizzbuzz (2020) by namelessUser on Tuesday March 16, 2021 @01:49PM (#26480283)
If a^n = 0 (or 1) mod b, then a^(kn) = (a^n)^k = 0 (or 1) mod b for any positive integer k.

Therefore you need to pick a common multiple of 6 and 10.

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