As you say, The sun has surface area of 6 x 10^18 m^2. Earth has surface area of 5 x 10^14 m^2 for a ratio of 10^4.
IF you reflect all of this energy to the earth, the incoming energy per meter on the earth will be 10^4 higher than the energy per meter leaving the surface of the sun.
The surface of the sun is 5,700K and can use the Stefan–Boltzmann law to describe how hot the earth would have to be to radiate the same amount of energy. Earth would need 57,000K to match the the same output.
That temperature should still be enough to make a fair dent though.
Following that logic, couldn’t you still put a dyson mirror around thesis and earth raising the sun and earth temp above 5700? This would raise the temp of both above 5700.
This is where my understanding of optics and reflections breaks down. How much heat/kinetic energy is transferred to a mirror when it reflects a photon?
From a heat transfer perspective. the dyson sphere has 100,000X the surface area of the sun to radiate heat and 1/100,000 the photon flux hitting it's surface. Based on this I would expect it to be cooler.