Re:Radio users reminded not to use radios in crimes
by sangnoir on Wednesday January 20, 2021 @10:06AM
(#25847234)
You can split normally-distributed populations into 2 halves - "average" may also refer to median. Also, by definition, half the population has an IQ[1] less than 100 (which is the mean). Gp is correct - most people are not as "smart as you are" if you are above average (IQ).
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Re:Radio users reminded not to use radios in crimes
by chrisseaton on Wednesday January 20, 2021 @10:42AM
(#25847706)
Do you know the term 'histogram'? Think about three pillars superimposed on the image you can see in the Wikipedia link - people around the middle, people below the middle group, people above the middle group. Most people are in the middle group. Most people are about as smart as you. A smaller number people are less smart and a smaller number are more smart. Get it?
Re:Radio users reminded not to use radios in crimes
by sangnoir on Thursday January 21, 2021 @08:16PM
(#25867008)
> Most people are about as smart as you.
You're introducing fuzzy language/approximations, which I was avoiding: one can say - in absolute terms - that any person above the median is smarter than most of the population.
An IQ band of 85 to 115 has 68% of the population, but are those at the lower end "as smart" as the upper end? The accuracy of your statement depends entirely on how wide your histogram bands are.
Re:Radio users reminded not to use radios in crimes
by thaumasiotes on Wednesday January 20, 2021 @03:00PM
(#25851195)
> You can split normally-distributed populations into 2 halves - "average" may also refer to median.
In a normal distribution, "average" must always also refer to median; they are always the same value.
Re:Radio users reminded not to use radios in crimes
by sangnoir on Thursday January 21, 2021 @08:11PM
(#25866972)
> In a normal distribution, "average" must always also refer to median; they are always the same value.
...and mode too! I am well aware of the characteristics of a normal distribution (this is HN after all). I was contrasting parents insinuation that gp's assertion on halving only works with uniform distributions