void foo(/*restrict*/ bool* x, int* y) {
if (*x) {
printf("foo\n");
*y = 0;
}
if (*x) {
printf("bar\n");
}
}
Enabling strict aliasing is effectively an assertion that pointers of incompatible types will never point to the same data, so a write to y will never touch *x. restrict is an assertion to the compiler on that specific pointer that no other pointer aliases to it.I wish there was a C/C++ compiler flag for treating all pointers as __restrict__. However I guess that C/C++ standard libraries wouldn't work with this compiler option (and therefore this compiler option wouldn't be useful in practice).
So while it is true that by default Rust has a theoretical performance advantage (compared to C/C++) because it forbids aliasing pointers I wonder (doubt) whether this will cause Rust binaries to generally run faster than C/C++ binaries.
On the other hand Rust puts security first, so there are lots of array bounds checks in Rust programs (and not all of these bounds checks can be eliminated). Personally I think this feature deteriorates the performance of Rust programs much more than you gain by forbidding aliasing pointers.
Depends on how those programs were written. Iterators should avoid bounds checking for example.
Does that also hold for a "uint8_t"--which is often just a renamed unsigned char rather than being a genuine type of its own?
What I don't fully understand is: "GCC has the option -fstrict-aliasing which enables aliasing optimizations globally and expects you to ensure that nothing gets illegally aliased. This optimization is enabled for -O2 and -O3 I believe." (source: https://stackoverflow.com/a/7298596)
Doesn't this mean that C++ programs compiled in release mode behave as if all pointers are marked with __restrict?