Here are some functions that match that type signature:
map1 foo x:xs = [foo x]
mapR foo x:xs = append (mapR foo xs) foo x
mapI foo x:xs = foo x : mapI foo x:xs
Of course, we can create many more functions that arrange the values in other creative ways, that add more or fewer values etc. If the function isn't pure, we can also imagine many more dimensions of functions that do arbitrarily different things from what you would expect.If you want complete signatures without dependent types, you need functions which take only single values of different unknown types, like apply: (a -> b) -> a -> b. If you have more than one parameter of the same unknown type, you'll have some ambiguity already.
Non-dependent types can only be used to encode extremely simple properties of a program. They are certainly useful, but they are not in any way the be-all, end-all of static verification.
Right—we need to require foo id = id.
But since you can't compare 2 functions for equality, and you can't compare two arbitrary values for equality, then yes - your informal requirement is enough togethet with the type to force the function to be `map`.
fn min(x: int, y: int) -> int
fn max(x: int, y: int) -> int
The meaning of a computation changes depending on which one we use.I probably should have used a different word than "semantics" since that has a technical definition in the PL field...
This is not true. Consider the map function of a typical functional language with parametric polymorphism:
map : (a -> b) -> [a] -> [b]
That signature is complete, it covers everything there is to know about the function. And, except for trivial implementations, there is no way to implement it wrongly.
In some cases, one can even rule out trivial implementations and infer the correct implementations from the type signature alone.
In any case, there is no "semantically wrong" input to such a function. It is just a function and totally agnostic regarding your use case.