Re:Testing for Divisibility by 19
by cruegge on Monday November 23, 2020 @06:51AM
(#25185761)
It does double the residue, but modulo 19. 2 * 18 = 36 = 17 (mod 19) and 2 * 10 = 20 = 1 (mod 19). The reason is that the method consists essentially of two steps. (1) Subtract a suitable multiple of 19 to make the number a multiple of 10. (2) Divide by 10. And dividing by 10 is the same as multiplying by 2, since 2 * 10 = 20 = 1 (mod 19).
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