"def myFun(a: String, b: Double): Boolean = {...}" and then "obj.mapValues.myFun.forall(_)" or just anything similar.
And yes, Scala is exactly the language when you need safe and maintainable code with far less unit tests required than in Java. But you have to invest into it and sometimes it is simply not worth it. The Scala2 to Scala3 migration situation makes things even worse unfortunately.
And it will be even easier in Scala 3, where this pattern is coded into an even simpler feature: extensions.
It's a bit cumbersome and not very use-case oriented (mechanism over intention) and so Scala 3 has introduced extension methods[0].
This gives you exactly what you want.
Since Scala 3 is pretty much completely backwards compatible (and with the use of Tasty you can use Scala 3 code in Scala 2.x projects), so I don't see the migration as a big problem. The Scala team has spent a lot of work to make the transition as painless as possible.
[0] https://dotty.epfl.ch/docs/reference/contextual/extension-me...
Part of the release testing is building the community release[0], which is a large part of the relevant Scala F/OSS code out there.
Whether you consider that to be production ready you have to decide for yourself, I myself am pretty happy about it.
Keep in mind that for now Scala 2 style code will still be compiled and you can use existing Scala 2 code in your Scala 3 project. The migration should be pretty smooth.
This was just an example. It's not about filter at all but the general method chaining.
Here is example from D if I must:
real[] fun(int[] arr) {
return arr.map!(a => a.to!double / PI).array;
}
void main()
{
int[] arr = 100.iota.array; // [0, 1, 2, 3, ...]
real[] newArr = arr.map!(a=> a*2).array.fun); // [0, 0.63662, 1.27324, ...]
}
I don't know how you can chain a custom method "fun" to the output of the "map" in Scala without duck typing. Why is this not possible when all conditions type-wise are met? Why you can chain std methods like map, filter, reduce, fold etc. but not custom ones? // Need to define this once somewhere in your project
implicit class TrushExtension[A](anything: A) {
def |>[B](function: A => B) = function(anything)
}
// Your application code
def fun(arr: Iterable[Int]) = arr.map(_.toDouble / Math.PI)
val arr = 0 to 100
val newArr = arr.map(_*2) |> fun
newArr.foreach(println) // prints 0, 0.63662, 1.27324, ...
Execute or change the code here: https://scalafiddle.io/sf/WAKhZtJ/0This is maybe not exactly as convenient, but it comes pretty close.
"someA.someB.someC" becomes "someA |> someB |> someC".
"foo |> bar |> baz" just visually parses easier than "foo pipe bar pipe baz"
val t1 = MyType()
def fun(t: MyType, argument: Int) = argument
// can't do this yet
// t1.fun(42)
// In Scala 2 you use an implicit class to add methods to a type
implicit class MyEnrichedType(t: MyType) {
def fun(argument: Int) = fun(t, argument)
}
// In Scala 3 you use an extension
extension (t: MyType)
def fun(argument: Int) = fun(t, argument)
// now it can be done
t.fun(42)
Regarding your question about the stdlib methods being able to be chained: they are not special. They are defined for the type the methods return, so they can be used.Rejecting all kinds of implicits and then complaining about Scala missing features is a bit unfair. "Implicit"is a single keyword, but not a single feature. Implicit arguments, implicit conversions and implicit classes are not the same thing. Fortunately, Scala 3 will clear this misunderstanding.
val myFun = (a: String, b: Int) => b % 2 == 0
List("a" -> 1, "b" -> 2, "c" -> 3).map(myFun.tupled).forall(identity) // false
List("a" -> 2, "b" -> 4, "c" -> 6).map(myFun.tupled).forall(identity) // true
But I think that's not what you mean... are you maybe looking for the "thrush" / |> operator? Or do you have some example from another language that does a better job and show how it looks there?
E.g. "arr.customlyFiltered()" is easy to do. Or even easier "arr.filter(myCustomFilter)". If something doesn't work out for you, please feel free to use e.g. scalafiddle.io and make it example, then you will be helped! :)
Scala is indeed not a high performant language. It is as fast as Java and compiles as fast as Java if you only use Java's features. However, then why use Scala in the beginning?
Scala is great for writing very maintainable and reusable code, especially with a big team and a lot of business logic. It is also great to "glue" things together like you can do it with Python. For these things it has more than sufficient performance in my opinion.