Making the Monty Hall problem weirder but obvious

Re:Making the Monty Hall problem weirder but obvious by nobaelazum on Thursday October 08, 2020 @03:50AM (#24716894)

Some explanations of this problem are far too complicated. This is how I explain it.

1/3 of the time, you guess correctly on your initial guess. If you switch, you'd be wrong.

2/3 of the time, you guess incorrectly on your initial guess. If you switch, you're right.

So when switching, the expecting outcome 1/3 of the time is 0, but the expected outcome 2/3 of the time 1. (1/3)0 + (2/3)1 = 2/3

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Re:Making the Monty Hall problem weirder but obvious by kgwgk on Thursday October 08, 2020 @04:20AM (#24717073)

You have solved a different problem. You didn’t include in your a analysis the “he opens one of the other doors and there is a goat” bit.

The original problem is more complicated.

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