Why are you excluding the phase transition energy of the brine? Presumably you can calibrate the salinity so it freezes at around say... -15C, and set your freezer to -18C. That way it's absorbing heat more heat when it's colder, which is helpful if you want to keep your food frozen. The latent heat of water isn't of use to you if all your meat is already thawed.
Or you can have normal water which is frozen at -1c and liquid at 1c. Your pick.
The handy thing about the brine is that its absorbs heat at a temperature below that which everything else thaws. So as the brine thaws it keeps your freezer at -18c which means everything in it is still frozen.
I mentioned -18C because that is the recommended minimum temperature for freezers such that some foods can last almost indefinitely; certain chemical reactions are completely shut down.
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Water (liquid) - 4.80 J/g.K
Water (solid) - 2.108 J/g.K (transition 334 J/g)
Brine (liquid, 300g/L) - 2.48 J/g.K
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So 1 gram of water (s) going from -18C to 0C (liquid) is 373 J.
1 gram of brine (l) going from -18C to 0C is 44.64 J.
Seems like ice is a better choice? The phase transition requires a huge amount of energy.
Brine is 70% more dense than water, so if you do it by volume, one mL of brine would be 76 J, so better, but still only ~1/5 that of pure water.