Unsupervised translation of programming languages

Re:Unsupervised translation of programming languages by Animats on Tuesday June 09, 2020 @10:28PM (#23473273)

    Python 3.6.9 (default, Apr 18 2020, 01:56:04) 
    [GCC 8.4.0] on linux
    >>> n = 10
    >>> allocation = [42] * n
    >>> allocation
    [42, 42, 42, 42, 42, 42, 42, 42, 42, 42]

That's what "*" does on lists in Python. The idea is that "abc" + def" is "abcdef", and then they overgeneralized.

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Re:Unsupervised translation of programming languages by Hello71 on Tuesday June 09, 2020 @10:33PM (#23473302)

  $ cat test.c
  #include <stdio.h>
  #include <string.h>
  int main() {
      int n = 10;
      int allocation[n];
      memset(allocation, 42, sizeof(allocation));
      for(int i = 0; i < n; i ++)
          printf("%d\n", allocation[i]);
  }
  $ gcc test.c
  $ ./a.out
  707406378
  707406378
  707406378
  707406378
  707406378
  707406378
  707406378
  707406378
  707406378
  707406378

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Re:Unsupervised translation of programming languages by lunixbochs on Tuesday June 09, 2020 @10:33PM (#23473301)

memset() is bytewise, the only reason it works with -1 is all the bits are set in every bit width. 0xff repeated still ends up being -1 at int size (0xffffffff). But the byte 0x2a repeated will be something more like 0x2a2a2a2a, which is not equivalent to 0x2a.

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Re:Unsupervised translation of programming languages by Animats on Wednesday June 10, 2020 @01:47AM (#23474340)

Right. So the translation was idiomatic but wrong.

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Re:Unsupervised translation of programming languages by hoseja on Wednesday June 10, 2020 @08:15AM (#23476232)

I'd say the C++ was wrong/unclear. If you want all the ints in your array to be a certain number, use std::fill. If you want all their bits to be 1, use something like ~0 in the memset.

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