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A comment on Snowpack 2.0. Parent comment
O(n^[number]) = polynomial, with O(n^2) being quadratic.
O([a number]^n) = exponential.
I guess the authors aren't big on CS fundamentals?
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O(n^[number]) = polynomial, with O(n^2) being quadratic.
O([a number]^n) = exponential.
I guess the authors aren't big on CS fundamentals?