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Re:Most common phone interview question at Google by ayberk on Saturday May 02, 2020 @03:12PM (#23054134)
> Isn't that the point? You say it like it's a problem, but it screens for someone who's reasonably prepared, which is probably what Google wants to do because they really start looking for the super-world-tier people they employ, because I guess that takes more time and resources.

Definitely. That's why it makes a good question for the initial screening. If you can't come up with the O(N) solution, there's very little chance you'll pass the on-site interviews.

> Doesn't the blog post already include a single-pass solution that works on a small alphabet?

It's actually two passes: one to create the set, and one more again to find the character. There's a solution you can do in only one pass through the string and one through the alphabet. Complexity is the same, but it's far fewer operations for the specific example given.

Re:Most common phone interview question at Google by chrisseaton on Saturday May 02, 2020 @03:15PM (#23054155)
> It's actually two passes: one to create the set, and one more again to find the character.

Those are combined into a single pass in the example in the article, aren't they?

Re:Most common phone interview question at Google by bootloop on Saturday May 02, 2020 @03:21PM (#23054194)
Yea I don't understand what the parent comment wants to say. You need to have a lookup structure (even if its only a bit) and then you can do one pass over the string. The lookup or adding a character doesn't count as a pass. And there is no way to omit this anyway.