If we say that infinitesimals exist, it still happens that 1 = 0.999…. It just happens that 0.999 ≠ 1 - 𝛚.
0.999… = 1 is a property of the way we write some rational numbers, not of the number system itself.
Re:0.999...= 1
by tomtomtom1 on Tuesday April 28, 2020 @10:52AM
(#23007545)
wouldn't 0.999.. be equal to 1 - 10^w since it's only a countably finite series of nines.
0.999...9 with a countable finite amount of nines is clearly less than 1.
0.999... with infinite nines is equal to 1.
Re:0.999...= 1
by tomtomtom1 on Thursday April 30, 2020 @01:19AM
(#23027674)
sorry I typoed I meant, countably infinite.
by w I meant the ordinal.
Re:0.999...= 1
by marcosdumay on Tuesday April 28, 2020 @10:50AM
(#23007535)
I have never seen a number system with infinitesimals where the addition wasn't updated to ignore smaller classes if they come with larger ones.
That is, for any number system I've seen, 1 = 1 + dx, and infinity = infinity + 100.
Re:0.999...= 1
by MaxBarraclough on Tuesday April 28, 2020 @05:49AM
(#23005344)
The obvious one seems terrible enough, that division is no longer the inverse of multiplication: (1/3)*3 != 1
Nonstandard analysis exists (with infinitesimal and infinite numbers) , but 1/3 and 9/9 is the same there. The problem is that the numbers 0.333... and 0.999... don't really exist.
Re:0.999...= 1
by LudwigNagasena on Tuesday April 28, 2020 @10:03AM
(#23007054)
Completeness is one of the most important properties of real numbers. Basically, you will have to completely throw away real analysis.
Re:0.999...= 1
by 2OEH8eoCRo0 on Tuesday April 28, 2020 @11:28AM
(#23007923)
1/3 does equal 0.3.. though.
what are the properties that we would lose?