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Re:0.999...= 1 by atq2119 on Tuesday April 28, 2020 @04:20AM (#23004839)
The crux of the matter is that you have to define what things like "0.3333..." mean in the first place. Any reasonable definition of it as a representation of a real number is going to lead to it being equal to 1/3.

If you want to redefine it explicitly as not a real number, you can do that, and maybe even get to some amusing math that way, but you're no longer talking the same language as the rest of the world.

Re:0.999...= 1 by tomtomtom1 on Tuesday April 28, 2020 @05:02AM (#23005109)
>"but you're no longer talking the same language as the rest of the world"

yes, in the standard real numbers 1 = 0.999.., but people have dealt with numbers like "pi" and "sqrt(2)" before the standard real numbers were defined.

Hence the question, if we define such a system such as 0.333... != 1/3. what are the consequences?

by 0.3333... I mean a countably infinite sequence of 3s.

Re:0.999...= 1 by atq2119 on Tuesday April 28, 2020 @05:35AM (#23005255)
I think an important distinction is that in those "old days", people were largely working in what we now know to be subsets of real numbers, and the same conclusion applies there.

If you want to go to supersets of real numbers, you may be interested in https://en.wikipedia.org/wiki/Surreal_number

Re:0.999...= 1 by Scarblac on Tuesday April 28, 2020 @10:29AM (#23007310)
If 0.333... != 1/3, then they are different numbers and the expression 1/3 - 0.333... must have some value different from zero. What is that value?