You must count how many special letters (like e, o, s) you have, and how many normal letters (all the other) you have.

In the example there are 6 special letters (two s's, one o and three e's). And there are 12 normal letters.

The total number of combinations is 2^12 * 3^6 = 2,985,984

It's in the brute force range, so you can get the list if you want using the programs linked in other comments. But password verifications have usually some protection to prevent brute force, like using a slow algorithm and adding some delays between tries.