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Re:The Great $50M African IP Address Heist by getpolarized on Wednesday December 11, 2019 @07:06PM (#21768141)
For spam purposes, IPv6 is just as rare as IPv4... you can generally assume that anyone in a /64 is the same owner.

... so really if you have 1000 IPv4 or 1000 /64 IPv6 it's about the same number of IPs that you can use to spam from.

Re:The Great $50M African IP Address Heist by oefrha on Wednesday December 11, 2019 @09:14PM (#21768739)
> IPv6 is just as rare as IPv4

Well, it’s not? There are 2^64 /64 IPv6s compared to 2^32 IPv4s in total. Unless you meant to say a /64 is as expensive as an IPv4.

Re:The Great $50M African IP Address Heist by jessant on Monday December 16, 2019 @08:59AM (#21802995)
I think they mean rare in terms of usage? As in you are as unlikely to encounter an ipv6 address as compared to the amount of v6 addresses.
Re:The Great $50M African IP Address Heist by proto-n on Wednesday December 11, 2019 @07:19PM (#21768219)
I'm not sure how tolerated this is on HN, but I'm lazy to research background on this. Could you please explain what a /64 is and why it is significant in this regard?
Re:The Great $50M African IP Address Heist by tgsovlerkhgsel on Wednesday December 11, 2019 @07:33PM (#21768290)
A netblock. A "/n" means "a block of IP addresses where the first n bits are the same".

This comes from the CIDR notation 192.168.1.0/24 indicating the netblock from 192.168.1.0 - 192.168.1.255.

So the number after the slash corresponds to a network size. The smaller the number, the more bits are variable, i.e. the bigger the netblock.

An IPv4 /24 has 32 (address length) - 24 = 8 bits that are variable, i.e. 2^8 addresses. A /18 would have 32-18 = 14 variable bits, i.e. 2^14 addresses.

In IPv6, the address length is 128. A /64 (which happens to be the smallest routable network size in IPv6) is 2^64 addresses - but because it's easy to get large IPv6 netblocks (typical ISP allocations are /64, /56, and you can often get a /48 with relative ease), for abuse blocking purposes, you generally treat the entire /64 or even /56 as one entity (i.e. you ignore the rightmost 64 or 72 bits).

A /56 is 2^8 separate /64s. A /48 is 2^16 separate /64s.

Re:The Great $50M African IP Address Heist by proto-n on Wednesday December 11, 2019 @07:41PM (#21768334)
That was very informative for me, thanks!
Re:The Great $50M African IP Address Heist by faster on Wednesday December 11, 2019 @07:26PM (#21768258)
From Wikipedia: "The standard size of a subnet in IPv6 is 2^64 addresses, more than 4 billion times the size of the entire IPv4 address space."

What he's saying is that one /64 address allocation is as useful to a spammer as a single IPv4 address.

Re:The Great $50M African IP Address Heist by edoceo on Wednesday December 11, 2019 @09:36PM (#21768824)
Want to also add it's called CIDR notation - or that's what I've learned - and that term has loads of good results
Re:The Great $50M African IP Address Heist by sjwright on Wednesday December 11, 2019 @07:35PM (#21768299)
Since none of us know exactly how much you already know about IP routing, we’ll likely either waste time providing an answer that assumes knowledge you don’t yet have, or waste time providing extraneous detail you don’t need.

I suggest googling something along the lines of “ipv6 allocation 56 64“ sans quotes.

[Edit: never mind; the HN community seems quite generous with their time today.]

Re:The Great $50M African IP Address Heist by duelingjello on Wednesday December 11, 2019 @07:41PM (#21768331)
The problem is that thinking for someone else doesn't "teach them to fish (learn independently)" and "be the change you seek," rather it enables co-dependency on others.
Re:The Great $50M African IP Address Heist by macintux on Wednesday December 11, 2019 @08:24PM (#21768531)
Conversely, searching for the meaning of a forward slash is not the simplest thing in the world.