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Re:The polynomial algorithm for 3-SAT problem (or P=NP) by RiderOfGiraffes on Thursday January 20, 2011 @12:53PM (#2124507)
By definition, a problem P is NPC if:

a. P is in NP, and

b. Every problem in NP can be converted to an instance of P.

Consider any two problems in NPC, P and Q. Then each is in NP, and each can be converted to the other. They are therefore equivalent.

QED.

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