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Re:The polynomial algorithm for 3-SAT problem (or P=NP) by anorwell on Thursday January 20, 2011 @01:38AM (#2122906)
If a single NP-Complete problem is in P, then P=NP. This is what NP-Complete means. In particular, factoring would be in P. Conversely, factoring is not NP-complete, so if factoring were in P, we could not draw any conclusions about P=?NP.

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