Re:AMD's Upcoming Ryzen 9 3900 Listed with 12 Zen 2 Cores at...
by lpmay on Friday September 27, 2019 @11:12AM
(#21092838)
No, the power consumed is equal. The capacitance doesn't stop charging at time tao as you imply, it continues to charge until it reaches the final driving voltage, which is why integrating to infinity is a (very) much closer approximation
Re:AMD's Upcoming Ryzen 9 3900 Listed with 12 Zen 2 Cores at...
by Buraksr on Friday September 27, 2019 @12:17PM
(#21093566)
What I am meaning is the input to the transistor on a chip is highly volatile, so the aproxmation of its power consumption using infinite or long periods of time of a single value is misleading.
If a transistor is only reciving 5v than it is fair to say the power consumed is equal.
But realisticly the input could change every clock cycle and we would see the cases vary.
The reason I only integrate to tao was to show if the input switches before t=infinity then a diffrence between cases clearly manifest. But as you say, when it does not switch for time t>>tao the diffrence is small.
1 Ohm Case : P_res = integral exp(-2t) from 0 to tao -> .4323J 1/2 Ohm Case : P_res = integral 2*exp(-4t) from 0 to tao -> .4908J
Of course the effect diminishes greatly (to zero as you showed) as the switching time increases. But we are dealing with a great number of transistors switching very many times so the effect is still noticeable given timings are tight enough.
The thought on power savings as you mention is interesting but i am unsure off the top of my head of it.