Re:Are black holes made of dark energy?
by gus_massa on Wednesday September 11, 2019 @01:10PM
(#20942392)
No. The solution to the problem you are proposing is well known and is part of any (advanced?) QM course, and it doesn't involve dark matter or dark energy.
In an harmonic oscillator (an ideal perfect spring with an ideal punctual mass) the energies are (2n+1)ħ/2*ω. They are all multiples of the minimal value for this oscillator. Note that it is a different set of values for each oscillator.
Each of these energies is associated with a wavefunction with a well defined energy. Combining all these wavefunctions you can represent any wavefunction. (The technical term is "orthonormal base", or simply "base".) This is easy to prove. More details in https://en.wikipedia.org/wiki/Quantum_harmonic_oscillator
So if you try to put the oscillator in a state that is not a wavefunction with a well defined energy, the state can be represented as a linear combination of the wavefunction with a well defined energy, and it will evolve following the laws of QM. It will not get transformed to dark energy or dark matter or get lost by damping.
If you later make measure the energy of the harmonic oscillator, the arbitrary wavefunction will colapse to a wavefunction with a well defined energy, and the probabilities are easy to calculate knowing how the initial state was decomposed in wavefunction with a well defined energy. If you measure the position or speed, the calculation is similar but there are a few more technical details.
In a more realistic system like an Hydrogen atoms, the energies are not multiples of a minimal value, the energies are like -E0/n^2. The corresponding wavefunctions are a base anyway, so any initial state can be decomposed in wavefunction with a well defined energy (that sometimes are calles "orbitals", but sometimes more general states are called "orbitals"). So there is no a fundamental frequency, there is no a minimal energy that is the divisor of all the energies, there is no dark energy.
In atoms with more electrons the calculations are more complicated, there is no nice formula for the energies, but is anyway possible to decompose any initial state without using dark energy.
In an harmonic oscillator (an ideal perfect spring with an ideal punctual mass) the energies are (2n+1)ħ/2*ω. They are all multiples of the minimal value for this oscillator. Note that it is a different set of values for each oscillator.
Each of these energies is associated with a wavefunction with a well defined energy. Combining all these wavefunctions you can represent any wavefunction. (The technical term is "orthonormal base", or simply "base".) This is easy to prove. More details in https://en.wikipedia.org/wiki/Quantum_harmonic_oscillator
So if you try to put the oscillator in a state that is not a wavefunction with a well defined energy, the state can be represented as a linear combination of the wavefunction with a well defined energy, and it will evolve following the laws of QM. It will not get transformed to dark energy or dark matter or get lost by damping.
If you later make measure the energy of the harmonic oscillator, the arbitrary wavefunction will colapse to a wavefunction with a well defined energy, and the probabilities are easy to calculate knowing how the initial state was decomposed in wavefunction with a well defined energy. If you measure the position or speed, the calculation is similar but there are a few more technical details.
In a more realistic system like an Hydrogen atoms, the energies are not multiples of a minimal value, the energies are like -E0/n^2. The corresponding wavefunctions are a base anyway, so any initial state can be decomposed in wavefunction with a well defined energy (that sometimes are calles "orbitals", but sometimes more general states are called "orbitals"). So there is no a fundamental frequency, there is no a minimal energy that is the divisor of all the energies, there is no dark energy.
In atoms with more electrons the calculations are more complicated, there is no nice formula for the energies, but is anyway possible to decompose any initial state without using dark energy.