Re:Mathematicians have found a new way to multiply two numbe...
by MrEldritch on Friday March 29, 2019 @03:07PM
(#19524576)
The reason it isn't actually important to have a specific algorithmic implementation is that - like other exotic multiplication algorithms with better big-O complexity than the usual ones - the constant factors are much, much bigger, to the point where they would only become noticeably faster for absurdly huge integers. The theoretical aspect of this is the interesting part.
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Re:Mathematicians have found a new way to multiply two numbe...
by db48x on Saturday March 30, 2019 @02:23AM
(#19528084)
In fact, in this case the algorithm is only intended for numbers with 2^4096 bits. See section 5 of the paper:
In this section we present the main integer multiplication
algorithm. We actually give a family of algorithms,
parameterised by a dimension parameter d > 2. Let n_0 :=
2^(d^12) > 2^4096, and suppose that we wish to multiply
integers with n bits. For n < n_0, we may use any convenient
base-case multiplication algorithm, such as the classical
O(n^2) algorithm.