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Re:Mathematicians have found a new way to multiply two numbe... by MrEldritch on Friday March 29, 2019 @03:07PM (#19524576)
The reason it isn't actually important to have a specific algorithmic implementation is that - like other exotic multiplication algorithms with better big-O complexity than the usual ones - the constant factors are much, much bigger, to the point where they would only become noticeably faster for absurdly huge integers. The theoretical aspect of this is the interesting part.
Re:Mathematicians have found a new way to multiply two numbe... by db48x on Saturday March 30, 2019 @02:23AM (#19528084)
In fact, in this case the algorithm is only intended for numbers with 2^4096 bits. See section 5 of the paper:

  In this section we present the main integer multiplication
  algorithm. We actually give a family of algorithms,
  parameterised by a dimension parameter d > 2. Let n_0 :=
  2^(d^12) > 2^4096, and suppose that we wish to multiply
  integers with n bits. For n < n_0, we may use any convenient
  base-case multiplication algorithm, such as the classical
  O(n^2) algorithm.