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A comment on An interesting article on probability and collectibles.
> and `(1/1 + 1/2 + 1/3 + 1/4 + ... + 1/(N-1) + 1/N)` converges to ln(N) as N grows, so the total number of purchases will be O(N * ln(N))
A logarithm is much easier to think about than the un-shrunk harmonic series.
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> and `(1/1 + 1/2 + 1/3 + 1/4 + ... + 1/(N-1) + 1/N)` converges to ln(N) as N grows, so the total number of purchases will be O(N * ln(N))
A logarithm is much easier to think about than the un-shrunk harmonic series.