>>> lookup = {}
>>> for (x, lookup[x]) in ('ab', 'cd', 'ef'):
... pass
...
>>> lookup
{'a': 'b', 'c': 'd', 'e': 'f'}
This makes is much more clear that there is just a double assignment, and that comprehension are pretty close to regular `for` statement.(this was a great example btw -- I write python3 a lot, and I was staring at it for a long time before Icould figure it out)
1. The syntax of comprehensions led me to think that they introduce some kind of a variable binding, such as `let` in many Lisps, and that binding `lookup[x]` would have been a syntax error. Of course Python didn't introduce anything like that for comprehensions, and it's just a normal assignment operation, with an extra scope inserted in Python 3 to stop `x` leaking into the enclosing scope.
2. Because of the swap idiom `x, y = y, x` I thought tuple assignment happens somehow in parallel, so my code should have caused an undefined variable error, even if it is not a syntax error. But of course it just evaluates the right hand side first and then assigns to the left hand side in left-to-right order, which the language reference https://docs.python.org/3/reference/simple_stmts.html#assign... notes "sometimes result[s] in confusion" (near the end of the section).