Why doesn't this code simply return a to z as the output?

Re:Why doesn't this code simply return a to z as the output? by zackattack on Friday November 05, 2010 @01:22AM (#1872136)

'z'++ is not 'aa'. 'z'++ is not even valid PHP. $z='z';$p=$z++; does nothing either.

it's only in the for-loop context.

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Re:Why doesn't this code simply return a to z as the output? by Nitramp on Friday November 05, 2010 @06:24AM (#1872631)

Not really, after $p = $z++ $p is 'z', $z is 'aa', as you'd kind-of expect. But the difference between literals and expressions/variable references of course just adds icing to the cake of bizareness.

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Re:Why doesn't this code simply return a to z as the output? by rythie on Friday November 05, 2010 @06:48AM (#1872667)

try...

<?php $z='z'; echo ++$z;

which produces 'aa'

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