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Re:Estimating the chances of something that hasn’t happened yet by agonmon on Sunday November 18, 2018 @04:45PM (#18482682)
I believe you have it right. Odds that all changes are improvements in 10 changes is: (.95)^10 Odds that at least one change is not improvement is: 1-(.95)^10 = 0.40

One could probably make an argument that not all trials are independent, but not sure what else down-voters saw.

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