Actually, since it's a ratio, the uniform distrubution is in the logarithmic domain, ie over [−log(3),+log(3)], so the probablity (assuming, for no good reason, that it is a uniform distribution), would be:

      log 3 − log 2
  1 − ───────────── ≈ 0.81546
      log 3 − log ⅓

or just over four fifths.

But as others have pointed out, the real answer is the question is broken, since we need a distribution for x, not a interval for x.