I don't think so. A type inferencer figures out types of expressions that don't have a type explicitly declared using information it has about other things that are declared.

A compile time type checker is expected to signal errors at compile time for programs whose types don't check out.

You can use a type inferencer without signaling any errors at compile time (for example, by deferring errors to runtime) and you can signal type errors at compile time even if you don't infer any types (like C compilers, that demand all variables have a declared type).