Re:PEP 572: Python assignment expressions has been accepted
by bilboa on Tuesday July 03, 2018 @02:25PM
(#17452560)
This is because the actual translation of `a + b` is a little more complicated. It's something like this:
In particular, the runtime seems to directly look for '__add__' in the object's __dict__, rather than just trying to invoke `__add__`, so your `__getattribute__` method isn't enough to make it work. If you add an actual `__add__` method to A your example will work.
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Re:PEP 572: Python assignment expressions has been accepted
by chriswarbo on Tuesday July 03, 2018 @03:23PM
(#17452949)
Yeah, I had a feeling the real 'expansion' would be more involved. I didn't know about the lookup in __dict__, that's good to know.
I'm reminded of PHP, where (at least in version 5.*) we could write:
$myObject->foo = function() { return "hello world"; };
$x = $myObject->foo;
$x(); // Hello world
$myObject->foo(); // Error: no such method 'foo'
(Taken from an old comment https://news.ycombinator.com/item?id=8119419 )
Re:PEP 572: Python assignment expressions has been accepted
by bilboa on Tuesday July 03, 2018 @05:28PM
(#17453736)
I found the official docs on how python special methods are looked up.
https://docs.python.org/3/reference/datamodel.html#special-l...
Apparently the runtime is even more picky than I showed. The method has to be defined on the object's type, not in the object's instance dictionary. So, really the lookup is something like:
if hasattr(type(a), '__add__'):
The link I provided explains the rationale for bypassing the instance dictionary and `__getattribute__` method.