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Re:PEP 572: Python assignment expressions has been accepted by blattimwind on Tuesday July 03, 2018 @08:27AM (#17449560)
> because it parses the same

Does not. One is addition, the other is in-place addition; they're different things and can behave differently. E.g. in "a += b" and "a = a + b", the former might not construct an intermediate object, but mutate the existing a.

Re:PEP 572: Python assignment expressions has been accepted by ben-schaaf on Tuesday July 03, 2018 @10:45AM (#17450607)
To be more specific for python: "a += b" -> "a = a.__iadd__(b)" "a = a + b" -> "a = a.__add__(b)"

"__iadd__" and "__add__" can do whatever they want.