I fixed your decryptor, the code is here, feel free to update no credit needed:

```cpp #include <iostream> #include <string> #include <vector> #include <fstream>

using namespace std;

char quirkdecode(int i, vector<string> dict);

int main(int argc, char argv) {

  // Load the dictionary  
  vector<string> dict;


  ifstream dictstream("doi.txt");
  string str;
  while (dictstream >> str) 
    dict.push_back(str);

  int i, j=0;
  while (cin >> i) {
    j ++;

    cout << quirkdecode(i,dict);
    if (j%5 == 0) cout << " ";
    if (j%75 == 0) cout << endl;
    //*/
  }

  cout << endl;
  return 0;

}

char quirkdecode(int i, vector<string> dict){ int delta=0;

  if (i==155) return 'a';// Beale Paper DOI has extra 'a' in "institute a new government"
  if (i>155)  delta-=1;  // Compensate for missing 'a' in doi.txt

  if (i>=242) delta+=1;  // 241 decrypts correct 246 not so delta  +1 @ [241-245] 
  if (i>=480) delta+=10; // 466 decrypts correct 485 not so delta +10 @ [267-285] known misnumbering
  if (i>=510) delta-=1;  // TODO presicely ocate
  if (i>=621) delta+=1;  // 620 decrypts correct 643 is not so delta  +1 @ [621-643]
  if (i>=667) delta+=1;  // 666 decrypts correct 807 is not so delta  +1 @ [667-807] ? double check ??

  // Hardcoded Jokers: NOTE 811 and 1005 are also the highest used codes, so it DOES seem to be intended as real
  if (i==811) return 'y' ;  // fundamentallY
  if (i==1005) return 'x' ; // seXes

  i+=delta;
  if (i<dict.size())
      return dict.at(i-1)[0];
  else
      return '!';

} ```

which gives:

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