That wasn't the question, though. Pi is the ratio between circumference and diameter of a perfect circle, whether or not you can create a perfect circle in your universe. We can't even create one in ours, and yet pi still "exists" here. Undoubtedly, wiggly-space mathematicians would also have a conception of pi, though it might be as esoteric to them as toroidial universes are to us.
To put that another way: Math has very simple axioms (e.g. set theory), and everything else derives from them. What theories can be proven from those axioms in this universe, can be proven from those axioms in any universe (and a universe that doesn't obey those axioms likely wouldn't "function" as a universe—it wouldn't have any reason to be causal, for example.) The maths describing a particular universe is its physics, which do change from universe to universe—however, those physics are all just different subsets of the set of mathematical physical models—which are, themselves, a subset of the mathematical theories provable from the axioms.
That said, I would very much like to understand why c = 2 x pi x r actually works. pi itself can be derived from pure mathematics, knowing the relationship e^(i x pi) = -1. So why a circle should have such a relationship with this constant is to me a fascinating question.
Because the "circles" we talk about in mathematics are found in Euclidean space—which is defined to have simple metric properties. Our own space is non-Euclidean.
2. When θ = pi, f(x) is periodic (the angle is such that f(x) intersects itself or "loops.")
3. The set of complex numbers is isomorphic to a 2D Euclidean plane. Therefore, a walk at angle i*pi through the set of complex numbers is isomorphic to a circle.
But mathematical constants like pi would remain the same, wouldn't it? A circle is a circle no matter what kind of universe it's in, so the ratio of the radius to the arc length would remain the same.
As I look at it, math is the universal truth of the universe, because everything is derived using the first principles.