Re:The Helium Factor and Hard Drive Failure Rates
by mattrices on Thursday May 03, 2018 @08:04PM
(#16991100)
He has a conductivity coefficent K (W/mK) = .151 and air = .026. Since everything else in heat flux eq is linear, approximately 5x rate of heat movement per degree that the HD is heated beyond surrounding air is expected.
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Re:The Helium Factor and Hard Drive Failure Rates
by tedunangst on Thursday May 03, 2018 @09:16PM
(#16991461)
Yeah, I can read a table of figures too, but what does that mean in the context of a hard drive? What percentage of the heat generated by the write heads (or whatever) is conducted away via air?
Re:The Helium Factor and Hard Drive Failure Rates
by mattrices on Friday May 04, 2018 @12:23PM
(#16995798)
That is a function of the design implemented. Since you can read a table of figures you can probably also plug them in the heat flux equation in with your own guesses at air gap distances and surface area. The relevant info is that 5 times the energy per degree difference are conducted, that is why any hot spots from friction are smoothed.