Re:Pythran: Crossing the Python Frontier [pdf]
by rlayton2 on Tuesday April 24, 2018 @06:42AM
(#16911397)
I believe the input should be a numpy array of floats which has a shape attribute
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Re:Pythran: Crossing the Python Frontier [pdf]
by serge-ss-paille on Tuesday April 24, 2018 @08:32AM
(#16911961)
(shameful author here)
One should read
def rosen_explicit_loop(x):
s = 0.
n = x.shape[0]
for i in range(0, n - 1):
s += 100. * (x[i + 1] - x[i] ** 2.) ** 2. + (1 - x[i]) ** 2
return s
(edited)
Re:Pythran: Crossing the Python Frontier [pdf]
by chestervonwinch on Tuesday April 24, 2018 @09:00AM
(#16912150)
...
n = x.shape[0]
Re:Pythran: Crossing the Python Frontier [pdf]
by quietbritishjim on Tuesday April 24, 2018 @12:22PM
(#16913987)
Or just len(x). This works perfectly well on numpy arrays and has the bonus that it works on regular lists/tuples of floats, so the first snippet doesn't rely on numpy.