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Re:Shortest bit sequence that's never been sent over the Int... by Retric on Thursday April 19, 2018 @10:22AM (#16876099)
Picture two coins and 2 flips and count the H's there (2x2) = 4 options and ((2x2) x 1/2 x 2(flips)) = 4 Heads.

HH, HT, TH, TT

However, if you count the sequences with at least one H there are (4-1) = 3 with at least 1 H (HH, HT, HT) as the HH eats up 2 H's.

Now, Picture 3 sided dice, that's (3x3) = 9 options. You will see ((3x3) x 1/3 x 2(flips)) = 6 2's.

00, 01, 02, 10, 11, 12, 20, 21, 22

However if you count there are (6 - 1) = 5 sequences with at least one 2 you get 02, 12, 20, 21, 22 as the 22 eats up an extra 2.

Now, what do you think happens with an N sided dice? What if N is 6.

PS: This seems less clear as I added more info...

Re:Shortest bit sequence that's never been sent over the Int... by rtkwe on Thursday April 19, 2018 @10:51AM (#16876366)
Yeah doing a brute force count of the possibilities the (6,6) option is double counted by the 1/6 + 1/6 method as two distinct possibilities. Or that's what it looks like is happening. Been too long since my college combinatorics class.