C++17 constexpr everything, or as much as the compiler can

Re:C++17 constexpr everything, or as much as the compiler can by uncle_bob on Thursday December 28, 2017 @06:27PM (#16026032)

Is there a C++ compiler that doesn't include 'make' and/or a 'make' replacement? There are linkage rules and even a few keywords just to allow linkage with code not generated by the compiler. It's very much part of the language.

'extern const int *table;'

Having a compile-time program create table would guarantee that it's created at compile time. Having a constexpr does not guarantee it would be done at compile-time, it silently degrades to run-time. If verifying requires an assembly listing, I see it less useful than the currently available tools.

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Re:C++17 constexpr everything, or as much as the compiler can by geezerjay on Friday December 29, 2017 @04:31AM (#16028574)

> Is there a C++ compiler that doesn't include 'make' and/or a 'make' replacement?

Yes, all of them.

Because 'make' and/or 'make' replacements have absolutely zero to do with a compiler. It is a build automation tool that essentially determines which target needs to be built based on which preceding targets have been altered. This has zero to do with what a compiler does.

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