Ok. Had to get this out quick... Back to work. Don't know if it will compile

<code> #include<iostream> using namespace std; int main() { for(int i = 1; i <= 100; ++i) { if(i%3==0 &&i%5==0) cout <<"Fizzbuzz ";

else if(i % 3==0) cout <<"FIzz "; else if(i%5==0) cout<<"buzz "; else cout << i << " "; } return 0; } </code>

  #include<iostream>
  using namespace std;
  int main() {
    for(int i = 1; i <= 100; ++i) {
      if(i%3==0 && i%5==0) cout <<"Fizzbuzz ";
      else
      if(i%3==0) cout <<"FIzz ";
      else
      if(i%5==0) cout<<"buzz ";
      else cout << i << " ";
      }
    return 0;
    }

Cool. Assuming you knocked that out as quickly as you suggest it shows that you've got good basic skills. Design and control of larger tasks/projects is untested, but it looks like you're well ahead of the basics.

Now here's a question: Do you find anything "unsatisfactory" about that code?

Besides not knowing how to post it properly...?

The looping sequence, I imagine, doesn't need the if else queries. Probably simpler way to code it. I am definitely untested with larger projects.

Something like... (Pseudocode)

    for( i= 1,100 )
    {
      if( i%3==0 ) { print( 'Fizz' ) }
      if( i%5==0 ) { print( 'Buzz' ) }
      print( '\n' )
    }

There's no need to treat FizzBuzz as a special case, as if the number is divisible by both it will have already met the conditions of the previous two statements.

I wonder if there's some magic you could sprinkle in to the iterator so it only iterates through numbers which are divisible by 3/5, ignoring the rest?

It probably wouldn't speed the operation up much (if at all) in this case, in a more complex real world scenario though it's best to look at every angle.

You haven't printed any of the other numbers. Read the spec more carefully. You still need to print 1, 2, 4, etc.