Re:Connections between Abstract Algebra and High School Alge...
by posterboy on Wednesday December 06, 2017 @03:43PM
(#15864785)
mod should be part of the signature of the ring, so you are not looking at pure multiplication. Then the domain would be still integral. Why wouldn't it?
Re:Connections between Abstract Algebra and High School Alge...
by opportune on Wednesday December 06, 2017 @03:46PM
(#15864823)
An integral domain is any commutative ring with no zero divisors (a,b are zero divisors if ab = 0 but a != 0, b != 0). In this case 2*2 = 0, so 2 is a zero divisor, so Z/4z = Z_4 is not an integral domain.
No, this is only true when you are doing multiplication in an integral domain.
https://en.wikipedia.org/wiki/Integral_domain
There are many rings where this is not true, like Z/nZ where n is not prime.