This is a fair point.
I guess my only response would be that some of the complexity classes in "some more efficiently than others, of course" might be impractical even if they are theoretically possible.
Which might be the saving grace should the equality turn out to be true, given the sheer number of scary-powerful algorithms that happen to be NP-complete. Certainly it'd be convenient if they were solvable, but... probably not safe, you understand?
Not really relevant here, though.
Any NP-complete problem reduces to any other, so if P=NP for any of them then it's true in general. Some more efficiently than others, of course.