Folding Promises in JavaScript

Re:Folding Promises in JavaScript by codefined on Thursday September 21, 2017 @10:21AM (#15303672)

    let accumulator = 0
    for (let item of array) {
      const value = await item
      // your code here
    }

Is identical, doesn't use 'cool' reduce features but is much easier to read in my opinion.

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Re:Folding Promises in JavaScript by todd3834 on Thursday September 21, 2017 @10:48AM (#15303945)

Wouldn’t this code only execute 1 promise at a time? I thought Promise.all allowed promises to be resolved in parallel

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Re:Folding Promises in JavaScript by theprotocol on Thursday September 21, 2017 @10:54AM (#15304020)

Indeed. You most likely should do `await Promise.all` and then do the reduction.

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Re:Folding Promises in JavaScript by dvlsg on Thursday September 21, 2017 @12:43PM (#15305236)

If item is already a promise, and not a function returning a promise, they would be "executing" in parallel.

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Re:Folding Promises in JavaScript by codefined on Thursday September 21, 2017 @10:53AM (#15304009)

Sorry, in the sense of being identical to the original code in the linked post (reduce), not the comment.

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