Re:Less Weird Quaternions Using Geometric Algebra
by logfromblammo on Monday August 07, 2017 @04:41PM
(#14951085)
The odd-ordered subalgebra (x, y, z, xyz) is symmetrical to the even-ordered subalgebra (1, xy, yz, zx), and can also represent quaternions.
Re:Less Weird Quaternions Using Geometric Algebra
by klodolph on Monday August 07, 2017 @05:21PM
(#14951377)
The odd-ordered subspace is a subspace, not a subalgebra, because multiplication is not closed.
Re:Less Weird Quaternions Using Geometric Algebra
by Govindae on Tuesday August 08, 2017 @10:23AM
(#14958008)
That doesn't work, the odd space isn't closed.
xx = 1
Re:Less Weird Quaternions Using Geometric Algebra
by logfromblammo on Tuesday August 08, 2017 @03:04PM
(#14961348)
I don't know what I was thinking....
For notation, we would often see the basis vectors named (e_1, e_2, e_3) instead of (x, y, z).
The quaternions are the even-ordered subalgebra of the 3D exterior algebra. The exterior algebra has scalars (1), vectors (x, y, z), bivectors (xy, yz, zx), and pseudoscalars (xyz). The even-ordered subalgebra is scalars and bivectors (1, xy, yz, zx). Adding or multiplying two even-ordered multivectors will always give you an even-ordered multivector, and 1 is even-ordered, so the even-ordered multivectors form a subalgebra.
We can also conceive of this subalgebra, the quaternions, as a Clifford algebra. Clifford algebras are generalizations of exterior algebras. Instead of saying v * v = 0, we can put something else on the RHS, and for quaternions we can start with just two basis vectors e_1 and e_2, and then define e_1 * e_1 = e_2 * e_2 = -1. The third basis vector for quaternions is then just e_1 * e_2.