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Re:Feynman on Fermat's Last Theorem (2016) by jwilk on Sunday August 06, 2017 @02:41PM (#14942719)
Here's a more straight-forward (but equally hand-wavy) way to calculate the probability that N is a perfect power:

P(N) ≈ (number of perfect powers near N) / (size of the neighborhood)

≈ (ⁿ√(N + r) − ⁿ√N) / r, for some smallish r

≈ d/dN (ⁿ√N)

= ⁿ√N / nN

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