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Re:Zuckerberg hires former Clinton pollster by lern_too_spel on Thursday August 03, 2017 @12:33AM (#14916975)
Canada has an independent organization draw its districts, which means there is effectively no gerrymandering. Under that system, a hypothetical US Parliament would be majority Democrat, and Clinton's popularity among elected officials in her party would have made her a shoo-in in the hypothetical PM election.
Re:Zuckerberg hires former Clinton pollster by Turing_Machine on Sunday August 06, 2017 @10:52AM (#14941526)
"Canada has an independent organization draw its districts, which means there is effectively no gerrymandering."

That just transfers the gerrymandering power from elected officials (who can be thrown out if they annoy the voters enough) to whoever gets appointed to an unelected "independent organization" (which can't be thrown out by the voters).

In practice, this "independent organization" is appointed by the Canadian parliament (i.e., by the political parties), so it is "independent" in name only.

To expand a bit, the very notion of an "independent organization" seems questionable. Who will make up this organization?

Career civil servants? They will be biased toward whichever party proposes to spend more money on civil servants.

Appointees by whichever party controls parliament (as appears to be the case in Canada)? The problem there should be obvious.

Proportional appointment on the basis of election results? Biased toward the major parties at the expense of minority parties.

And so on.

Not even a blind grid system is immune -- in that case where you set the origin of the grid can have a major effect.