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Re:Clojure Linear Algebra Refresher: Eigenvalues and Eigenve... by stablemap on Tuesday June 06, 2017 @12:21PM (#14498425)
What he gives is the identity matrix—multiply on the right by any 2x1 vector and you will get that vector back. So any such vector, provided it is not the zero vector, is an eigenvector with eigenvalue 1.

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