Re:Atomic Spins Evade Heisenberg Uncertainty Principle
by jeffwass on Monday April 03, 2017 @01:10PM
(#14024741)
Replying to your first paragraph.
You're casually ignoring how it got to eigenstate a in the first place. The particle is in an eigenstate a because it was acted on by the A operator.
If it was in an eigenstate b prior to this, or any other state that isn't a single eigenstate of A, the action of operator A disturbed that original state.
The HUP itself is a direct consequence of measuring the uncertainty of two noncommuting operators, and its derivation is a fairly straightforward, though a bit annoying, mathematical result.
You're casually ignoring how it got to eigenstate a in the first place. The particle is in an eigenstate a because it was acted on by the A operator.
If it was in an eigenstate b prior to this, or any other state that isn't a single eigenstate of A, the action of operator A disturbed that original state.
The HUP itself is a direct consequence of measuring the uncertainty of two noncommuting operators, and its derivation is a fairly straightforward, though a bit annoying, mathematical result.