Re:Cantor diagonalisation
by _rpd on Saturday March 11, 2017 @01:35PM
(#13846520)
> This is completely uncontroversial
I think it is still intuitively surprising that some infinite sets somehow have more elements than other infinite sets. The powerset operator is very special because it can create this difference.
Re:Cantor diagonalisation
by Smaug123 on Saturday March 11, 2017 @01:42PM
(#13846550)
I suppose I really meant "why should one expect that f might be injective anyway?" Once you're no longer in the context of a set like N which is very familiar, there's just no obvious reason for the theorem to be false.
I think it is still intuitively surprising that some infinite sets somehow have more elements than other infinite sets. The powerset operator is very special because it can create this difference.