Re:About the irrationality of e=2.718... (1840)
by conistonwater on Tuesday January 24, 2017 @01:20PM
(#13473978)
As pointed out in the annotation, isn't the case $e^2$ just exactly the same proof but for the special case $c=0$? And in any case, if $e^2$ were rational, then $e$ could only be rational or a quadratic irrationality.
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Re:About the irrationality of e=2.718... (1840)
by siegelzero on Tuesday January 24, 2017 @02:46PM
(#13474789)
Yeah, this proof seems to work. I was thinking of the case where you attack $e^2$ directly, instead of going after both $e$ and $e^{-1}$.