Re:The Rust module system is too confusing
by Thiez on Wednesday January 11, 2017 @05:44PM
(#13378159)
I suppose it can get a little silly when you mix closures without arguments and the logical 'or' operator', e.g.:
// prints 'true'
println!("{}", true||(||true)()||(||true)());
Of course you wouldn't actually do this unless you're being intentionally obscure. Another favorite of mine: // prints '()'
println!("{:?}", (||||||||||())()()()()());
But I can't recall ever running into such silly code, in practice the closure syntax and logical or do not lead to confusion (imho, ymmv).
Re:The Rust module system is too confusing
by MoSal on Wednesday January 11, 2017 @06:41PM
(#13378537)
> in practice the closure syntax and logical or do not lead to confusion (imho, ymmv).
That's true. But put your self in the mind of a C developer looking at Rust code for the first time:
if a || b {
println!("True");
}
Cool.Then:
thread::spawn(|| println!("Hello from a thread!"););
What? What is the logical or doing there?----
IIRC, there are also cases where you have to write `& &` instead of `&&` to not confuse the compiler. That's a design/practical issue.
Both those issues would have been avoided if literal `and`/`or` were used.
I find it interesting how the only thing that momentarily confused me, as a C developer, about Rust syntax, was caused by Rust authors not wanting to syntactically deviate too much from C.
I only knew(and liked) C reasonably well before Rust. And nothing felt obscure when I started learning it.
I can only remember not getting what `||` meant (in the context of defining a closure without args). The positional meaning of `||` and `&&` is the only thing, I can recall right now, that can be considered obscure syntactically (for C developers at least) . They should have gone with literal `and`/`or` for the operators IMHO.